Iniciante
a) ![Mg_3As_2](https://i0.wp.com/noic.com.br/wp-content/plugins/latex/cache/tex_39dc5a7a3229801a943d8295730d78e5.gif?w=640&ssl=1)
b)![In_2S_3](https://i0.wp.com/noic.com.br/wp-content/plugins/latex/cache/tex_a59c45fa0fd0d4b17bb40d55a9b1f633.gif?w=640&ssl=1)
c)![AlH_3](https://i0.wp.com/noic.com.br/wp-content/plugins/latex/cache/tex_9b725adf13acfceb1a9da1612df7fee7.gif?w=640&ssl=1)
d)![H_2Te](https://i0.wp.com/noic.com.br/wp-content/plugins/latex/cache/tex_da641c4b96cd1c49986dccd3ba7207ac.gif?w=640&ssl=1)
e)![BiF_3](https://i0.wp.com/noic.com.br/wp-content/plugins/latex/cache/tex_841df07c3034e13c3de35a06c2bf4202.gif?w=640&ssl=1)
![Mg_3As_2](https://i0.wp.com/noic.com.br/wp-content/plugins/latex/cache/tex_39dc5a7a3229801a943d8295730d78e5.gif?w=640&ssl=1)
b)
![In_2S_3](https://i0.wp.com/noic.com.br/wp-content/plugins/latex/cache/tex_a59c45fa0fd0d4b17bb40d55a9b1f633.gif?w=640&ssl=1)
c)
![AlH_3](https://i0.wp.com/noic.com.br/wp-content/plugins/latex/cache/tex_9b725adf13acfceb1a9da1612df7fee7.gif?w=640&ssl=1)
d)
![H_2Te](https://i0.wp.com/noic.com.br/wp-content/plugins/latex/cache/tex_da641c4b96cd1c49986dccd3ba7207ac.gif?w=640&ssl=1)
e)
![BiF_3](https://i0.wp.com/noic.com.br/wp-content/plugins/latex/cache/tex_841df07c3034e13c3de35a06c2bf4202.gif?w=640&ssl=1)
Intermediário
O ânion do composto dissolvido pode ser facilmente identificado pela sua reação com o cátion
, que precipita na presença de
,
ou
. Como o precipitado formado é branco, evidencia-se a presença de cloreto na solução (precipitados com outros haletos têm tons amarelados). Assim, teríamos como resposta
,
.
De fato, esse é o único composto possível, uma vez que apenas o
contém ambos um cátion capaz de formar hidroxocomplexo e um ânion que forma precipitado branco ao reagir com
.
![Ag^+](https://i0.wp.com/noic.com.br/wp-content/plugins/latex/cache/tex_01cda9fab2339d4e1ba056d980991d9a.gif?w=640&ssl=1)
![Cl^-](https://i0.wp.com/noic.com.br/wp-content/plugins/latex/cache/tex_79201738ae25ac66841f69034f11bb73.gif?w=640&ssl=1)
![Br^-](https://i0.wp.com/noic.com.br/wp-content/plugins/latex/cache/tex_a48c62c3d522bbbc8875e07142a0b271.gif?w=640&ssl=1)
![I^-](https://i0.wp.com/noic.com.br/wp-content/plugins/latex/cache/tex_a3ba8552b3f34fb369be3f10b8f34cb2.gif?w=640&ssl=1)
![(d)](https://i0.wp.com/noic.com.br/wp-content/plugins/latex/cache/tex_625486c67a9a05320a216cf35bf53868.gif?w=640&ssl=1)
![AlCl_3](https://i0.wp.com/noic.com.br/wp-content/plugins/latex/cache/tex_e7852e09a3f9bba6f5030ca3f6331af2.gif?w=640&ssl=1)
De fato, esse é o único composto possível, uma vez que apenas o
![AlCl_3](https://i0.wp.com/noic.com.br/wp-content/plugins/latex/cache/tex_e7852e09a3f9bba6f5030ca3f6331af2.gif?w=640&ssl=1)
![Ag^+](https://i0.wp.com/noic.com.br/wp-content/plugins/latex/cache/tex_01cda9fab2339d4e1ba056d980991d9a.gif?w=640&ssl=1)
Avançado
a) O potencial da semi-reação pode ser obtido a partir da soma dos
G's individuais.
+
+
G =
![\Delta](https://i0.wp.com/noic.com.br/wp-content/plugins/latex/cache/tex_967878d1da852d4b07a961e3168b0fff.gif?w=640&ssl=1)
![PbC_2O_4](https://i0.wp.com/noic.com.br/wp-content/plugins/latex/cache/tex_fba7fa658581836840315ad2545d5629.gif?w=640&ssl=1)
![2e^-](https://i0.wp.com/noic.com.br/wp-content/plugins/latex/cache/tex_28a775c7583eda752991b3e5c34c292a.gif?w=640&ssl=1)
![\longrightarrow](https://i0.wp.com/noic.com.br/wp-content/plugins/latex/cache/tex_78d9dc6c665f9a9e2b81c280a13771b7.gif?w=640&ssl=1)
![Pb](https://i0.wp.com/noic.com.br/wp-content/plugins/latex/cache/tex_0789e060643d0f6b1d638830a383387b.gif?w=640&ssl=1)
![C_2O_4^{2-}](https://i0.wp.com/noic.com.br/wp-content/plugins/latex/cache/tex_b0a1d155a898dc464f9ad653661164c3.gif?w=640&ssl=1)
![\Delta](https://i0.wp.com/noic.com.br/wp-content/plugins/latex/cache/tex_967878d1da852d4b07a961e3168b0fff.gif?w=640&ssl=1)
![-nFE](https://i0.wp.com/noic.com.br/wp-content/plugins/latex/cache/tex_967e91401ff009df44e3206f3598123c.gif?w=640&ssl=1)
=
+
![E = -0,394V](https://i0.wp.com/noic.com.br/wp-content/plugins/latex/cache/tex_bfdc9efd7beabf29ee96b7c03aaaa388.gif?w=640&ssl=1)
b)
![[Pb^{2+}]](https://i0.wp.com/noic.com.br/wp-content/plugins/latex/cache/tex_5ce476075e749cfcfe5d192b128a90a0.gif?w=640&ssl=1)
![10^{-8}](https://i0.wp.com/noic.com.br/wp-content/plugins/latex/cache/tex_6472b2f9e70aac629d7e2763a59f0066.gif?w=640&ssl=1)
c) O potencial pode ser calculado a partir das duas semi-reações:
i) + 2e-
Pb +
- (0,0592/2) log [
]
= -0,394 - 0,0296 log [0,025]
![E = -0,347V](https://i0.wp.com/noic.com.br/wp-content/plugins/latex/cache/tex_911dadc64ccc535e5bab58523d2a3812.gif?w=640&ssl=1)
ii) Pb
+
Pb
![^{2+}](https://i0.wp.com/noic.com.br/wp-content/plugins/latex/cache/tex_b03c20a64e589e6b99b71dc41f22168b.gif?w=640&ssl=1)
![2 e-](https://i0.wp.com/noic.com.br/wp-content/plugins/latex/cache/tex_3ae28653dedfc471cbe346ec28804f8d.gif?w=640&ssl=1)
![\longrightarrow](https://i0.wp.com/noic.com.br/wp-content/plugins/latex/cache/tex_78d9dc6c665f9a9e2b81c280a13771b7.gif?w=640&ssl=1)
![E = E^o](https://i0.wp.com/noic.com.br/wp-content/plugins/latex/cache/tex_df1f3de0c06909c00615d81bcca7b705.gif?w=640&ssl=1)
![Pb^{2+}](https://i0.wp.com/noic.com.br/wp-content/plugins/latex/cache/tex_26168837a9ad0c8489e50a8341bd8fb7.gif?w=640&ssl=1)
![E](https://i0.wp.com/noic.com.br/wp-content/plugins/latex/cache/tex_3a3ea00cfc35332cedf6e5e9a32e94da.gif?w=640&ssl=1)
![10^{-8}](https://i0.wp.com/noic.com.br/wp-content/plugins/latex/cache/tex_6472b2f9e70aac629d7e2763a59f0066.gif?w=640&ssl=1)
![E = -0,347V](https://i0.wp.com/noic.com.br/wp-content/plugins/latex/cache/tex_911dadc64ccc535e5bab58523d2a3812.gif?w=640&ssl=1)